A simple random sample of 49 8th graders at a large suburban middle school indicated that 82% of them are involved with some type of after school activity. Find the 99% confidence interval that estimates the proportion of them that are involved in an after school activity.

0.142

Step-by-step explanation:

From the question, we identify the following parameters;

n = 49

p = 82% = 82/100 = 0.82

alpha, α = 1-0.99 = 0.01

Zα/2 = Z_0.005 = 2.575

margin of error = Zα/2 * √( p(1-p)/n)

Margin of error = 2.575 * √(0.82)(1-0.82)/49

Margin of error =0.1416005 which is approximately 0.142

answer

explanation

the area of a circle is calculated using the formula

or

we can use any of the above formulae to calculate the required. preferably, let us use the latter since the diameter is

we substitute the diameter into the formula to get:

this is the exact value for the area of the circle.

the correct answer is a