Esibu and Dela are in a part-time business manufacturing clock case. Esibu must work 4 hours and Dela 2 hours to complete one case for a grandmother clock. To build one case for a wall clock, Esibu must work 3 hours and Dela 4 hours. Neither partners wish to work more than 20 hours per week. If they receive GHC80.00 for each grandmother clock and GHC64.00 for each wall clock, how many of each should they build each week to maximize their profit?

Correct

To maximize their profit, Esibu must build 6 (2 grandmother clock and 4 wall clock) while Dela must build 8 (6 grandmother clock and 2 wall clock).

Step-by-step explanation:

Since they don't want to work for more than 20 hrs in a week

In-order to maximize the profit,

For Esibu,

2 grandmother clock = 4 hours ×2 = 8 hours

4 wall clock = 3 hours × 4 = 12 hours

Total hours = 20 hours.

For Dela,

6 grandmother clock = 2 hours × 6 = 12 hours

2 wall clock = 4 hours × 2 = 8 hours

Total hours = 20 hours.

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

answer: 323 is how many she has ☃☃⛄❄

step-by-step explanation: