Determine the points of intersection of the equation circumference x² + (y-3) ² = 25 with the coordinate axes.

(4, 0), (-4, 0), (0, -2), (0, 8)

Step-by-step explanation:

  (0, -2), (4, 0), (0, 8), (-4, 0)

Step-by-step explanation:

The y-intercepts are found by solving for y when x=0.

  (y -3)² = 25

  y -3 = ±5 . . . . . take the square root

  y = 3 ± 5 = {-2, 8}

The x-intercepts are found by solving for x when y=0.

  x² +(0-3)² = 25

  x² = 16 . . . . . . . . subtract 9

  x = ±4 . . . . . . . . .take the square root

The y-intercepts are (0, -2) and (0, 8).

The x-intercepts are (-4, 0) and (4, 0).

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5