The sum of five consecutive positive integers is 2020. Find the largest of these numbers.

406

Step-by-step explanation:

Five consecutive positive integers = x, (x+1), (x+2), (x+3), (x+4)

x + (x+1) + (x+2) + (x+3) + (x+4) = 2020

5x + 10 = 2020

5x = 2020-10

5x = 2010

x = 2010÷5

x = 402

The largest of the number is = x+4

x+4 = 402 + 4 = 406

angle addition postulate

2x=56

step-by-step explanation: