If a coin is tossed twice find the probability of getting a) 2 heads b) atleast 1 head c) no heads

a) 1/4

b) 3/4

c) 1/4

Step-by-step explanation:

Possible outcomes of two tosses of a coin:

HH

HT

TH

TT

There is a total of 4 possible outcomes.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

a) 2 heads

HH     <  1 desired outcome

HT

TH

TT

p(2 heads) = 1/4

b) at least 1 head

HH   \  

HT      }     < 3 desired outcomes

TH    /

TT

p(at least 1 head) = 3/4

c) no heads

HH

HT

TH

TT    < 1 desired outcome

p(no heads) = 1/4

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step-by-step explanation:

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,