Which equation satisfies all three pairs of a and b values listed in the table ? A) a-3b=10
B) 3a+ b=10
C) 3a-b=10
D) a+ 3b=10

The answer is option C.

3a - b = 10

Hope this helps you

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents