Tim wants to build a rectangular fence around his yard. He has 42 feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

Rectangular fence dimensions:

x = 14 ft

w = 7  ft

A  = 98 ft²

Step-by-step explanation:

Rectangular fence dimensions:

x   length      and     w  width

Then   x  =  2*w      ⇒     w = x/2

Perimeter is

p = 2*x + 2*w

p = 2*x + 2* x/2

p = 2*x + x

3*x = 42

x = 14  ft      and     w = 14/2      ⇒     w = 7  ft

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

3 is greater then both of those numbers