A 6-digit number has at least one even digit in its record. How many such numbers are there? (0 is an even digit)

884,375

Step-by-step explanation:

The first digit can't be 0, so there are 9×10⁵ = 900,000 possible six-digit numbers.

Of those, the number of six-digit numbers that have only odd digits is 5⁶ = 15,625.

Numbers with at least one even digit are all numbers that don't have only odd digits.  So the number of six-digit numbers with at least one even digit is:

900,000 − 15,625 = 884,375

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.