In △ABC, AD is the angle bisector of ∠A and BE is the angle bisector of ∠B. If AD intersects BE at point O, find m∠AOB given the following: b m∠A = 125°, m∠B = 33° quick I will give brainliest, need in 5 minutes!

∠AOB = 101°

Step-by-step explanation:

Given:

AD is the angle bisector of ∠A

BE is the angle bisector of ∠B.

∠A = 125°

∠B = 33°

Find:

∠AOB

Computation:

∠BAO = 125° / 2 = 62.5°

∠ABO = 33°/2 = 16.5°

So,

∠AOB + ∠BAO + ∠ABO = 180°

∠AOB + 62.5° + 16.5° = 180°

∠AOB = 101°

answer: what in the world is this

step-by-step explanation:

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.