A smartphone company found in a survey that 6% of people did not own a smartphone, 15% owned a smartphone only, 26% owned a smartphone and only a tablet, 32% owned a smartphone and only a computer, and 21% owned all three. If a person were selected at random, what is the probability that the person would own a smartphone only or a smartphone and computer

47%

Step-by-step explanation:

we are required to find the probability to randomly select from the union of those who own a smartphone only and those who own a smartphone and computer.

an addition of the subsets cover the entire set.

6 + 15 + 26 + 32 + 21 = 100%

let

p(A)= probability of smartphone only

p(B) = probability of smartphone and computer

p(A U B) = P(A) + P(B)

= 15% + 32%

= 47%

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925