Mathematics, 23.07.2020 01:01 BlueExorcistReaper
The radius of a right circular cone is increasing at a rate of 1.1 in/s while its height is decreasing at a rate of 2.4 in/s. At what rate is the volume of the cone changing when the radius is 109 in. and the height is 198 in.
Answers: 3
![\frac{dV}{dt} = \frac{1}{3}\pi [2rh\frac{dr}{dt} +r^2\frac{dh}{dt}]](/tpl/images/0711/4351/b8c9b.png)
![\frac{dV}{dt} = \frac{\pi}{3} [218*198*1.1+109^2*2.4]](/tpl/images/0711/4351/295f8.png)
![\frac{dV}{dt} = \frac{\pi}{3} [47480.4+28514.4]\\\\\frac{dV}{dt} = \frac{\pi}{3} [75994.8]\\\\ \frac{dV}{dt} = 3.142 [25331.6]\\\\ \frac{dV}{dt} =79591.8872 in^3/s](/tpl/images/0711/4351/46c01.png)
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The radius of a right circular cone is increasing at a rate of 1.1 in/s while its height is decreasi...
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