(04.02 LC) What is the solution to the following system of equations?
X - 3y = 6
2x + 2y = 4

(-1, 3)
(3, -1)
(1, -3)
(-3, 1)

The solution is

Step-by-step explanation:

x - 3y = 6 Equation 1

2x + 2y = 4 Equation 2

Make x the subject in equation 1 and substitute it into equation 2

That's

x = 6 + 3y

2( 6 + 3y ) + 2y = 4

Expand and simplify

12 + 6y + 2y = 4

8y = - 8

Divide both sides by 8

y = - 1

Substitute y = - 1 into x = 6 + 3y

That's

x = 6 + 3(-1)

x = 6 - 3

x = 3

x = 3 y = - 1

( 3 , - 1)

Hope this helps you

the first one

step-by-step explanation:

just id the test.

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula