In △ABC, AB=BC=29, and AC=42. What is the area of △ABC?

The area of △ABC is 420 square units.

The formula for calculating Heron's formula is expressed as √(s(s-a)(s-b)(s-c)  

where:

Get the value of "s"

s = (29+29+42)/ 2

s = 100/2

s = 50.

Get the required area:

Area = √50(50-29)(50-29(50-42)

Area = √176400

Area = 420.

Hence the area of △ABC is 420 square units.

Learn more on area of triangle here: link

420 unit^2.

Step-by-step explanation:

Use  the formula area = √(s(s-a)(s-b)(s-c)   where s = the semi-perimeter and ab and c are the 3 sides. (it is called Heron's Formula).

s = (29+29+42)/ 2

= 100/2

= 50.

Area = √50(50-29)(50-29(50-42)

= √176400

= 420.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

25% is the answer