If g(x) = 4x^2- 16 were shifted 5 units to the right and 2 down, what would the new equation be?
A. h(x) = 4(x - 18)^2 - 5
B. h(x) = 4(x + 5)^2 - 17
C. h(x) = 4(x - 5)^2 - 18
D. h(x) = 4(x - 5)^2 + 14

J= r + 9 because since jessica rode 9 more miles than roger, you add 9 miles to rogers mileage.

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.