Please help me with this question. refer to the image first. 5. The diagram below shows three circles. Circle A has a radius of 2 cm and circle B has a
radius of 1 cm.

PQ is a common tangent and all circles touch one another. Find the radius of the smallest
circle. PL5

The radius of the small circle is about 0.85 cm - 0.95 cm

Explanation: I am not completely sure but I drew the same figure with the same lengths as given and between both circles there is almost a gam of 2.5 - 3 cm and when we draw a circle between them the diameter is about 1.7 - 1.9 so dividing the diameter by 2 to get the radius we get 0.85 cm - 0.95 cm.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

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