A square has diagonals of length 10 cm. Find the sides of the square

5

Step-by-step explanation:

The diagonal divides the square into 2 right triangles.

let s be the side of the square with the diagonal being the hypotenuse.

Applying Pythagoras' identity to one right triangle, gives

s² + s² = 10² , that is

2s² = 100 ( divide both sides by 2 )

s² = 50 ( take the square root of both sides )

s = = = × = 5

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23