The graphed line shown below is y = 5 x minus 10. On a coordinate plane, a line goes through (2, 0) and (3, 5). Which equation, when graphed with the given equation, will form a system that has no solution? y = negative 5 x + 10 y = 5 (x + 2) y = 5 (x minus 2) y = negative 5 x minus 10 Mark this and return

The correct option is:

y = 5(x-2)

Step-by-step explanation:

The graphed line is;

y = 5x - 10

y = mx + c

Thus, slope of graphed line is equal to m=5.

Those line will have no solution which have are parallel to the graphed line (have a slope of 5) and passes through the given points.

Following lines have the slopes 5:

y= 5(x+2)

y= 5(x-2)

Check which equation satisfied points (2,0) and (3,5)

For (2,0)

y=5(x-2)

y=5(2-2)

y=0

For (3,5)

y=5(x-2)

y=5(3-2)

y=5

Thus, correct option is y = 5(x-2)

its b

step-by-step explanation:

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i