Can someone explain how to use sin cos and tan on right angled triangles

Round this however you need to

Explanation:

The reference angle is 56 degrees. The side 26.5 is adjacent to this angle as it is the leg closest to the angle (in contrast to the opposite leg or opposite side that is furthest from the reference angle)

The hypotenuse is d. The hypotenuse is always the longest side. The longest side is always opposite the largest angle of a triangle.

We will use the cosine ratio as it is the ratio of adjacent over hypotenuse

cos(angle) = adjacent/hypotenuse

cos(56) = 26.5/d

d*cos(56) = 26.5

d = 26.5/cos(56)

d = 47.3897287242421

You use your calculator for the last step shown above. Make sure your calculator is in degree mode. Round that value however you need to.

Here is the formula of sin cos tan :

sin x = opposite/hypotenuse

cos x = adjacent / hypotenuse

tan x = opposite / adjacent

d = hypotenuse

x = the angle known in your pic

like example if in your picture:

adjacent = 26.5

if want to find the d

cos x = adjacent / hypotenuse

cos 56 = 26.5 / d

d = 26.5 : cos(56)

d = 47.390 (3 significant figures)

and if want to find the opposite

tan x = opposite/adjacent

tan 56 = opposite/ 26.5

opposite = 26.5 × tan(56)

opposite = 39.288

-> Sorry if im wrong

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc