A rectangle has a width of x centimeters and a length 10 centimeters longer than the width. If the total perimeter is 220 centimeters, what is the measure of the length?

Step-by-step explanation:

Given the width of a rectangle W = x centimeters

If the  length is 10 centimeters longer than the width, then L = (10 + x)cm

Perimeter of the rectangle = 220 cm

To calculate the length, we need to first calculate the value of x. Using he formula for calculating the perimeter of a rectangle to get x;

Perimeter P = 2(L+W)

Substituting the value of the length and the width, we will have;

P = 2(10+x+x)

220 = 2(10+2x)

Dividing both sides by 2;

220/2 = 2(10+2x)/2

110 = 10+2x

2x = 110-10

2x = 100

x = 100/2

x = 50cm

Since the length of the rectangle L = 10+x

The length of the rectangle = 10+50 = 60 cm

Hence, the measure of the length is 60 cm

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source: