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Mathematics, 22.07.2020 01:01 Daisysolis136

How would I solve? Please help! Use the quadratic formula -b + √b² - 4ac
to solve for the x-intercepts in the
following equations.
a.
0 = x²- 2x - 15
a= ? b= -?
c=?
b.
The x-intercepts of the function y = x² – 2x – 15 are ( ?,0) and -?,0) (A. K.)
c.
The x-value of the vertex, located halfway between the two x-intercepts is: _?(A. K.)
d.
After you plug in the x-value of the vertex back into the function
y = x²- 2x - 15, you get the y-value of the vertex, _? (A. K.)
e.
The vertex, written as a paired coordinate is (_?_,_?_).

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How would I solve? Please help! Use the quadratic formula -b + √b² - 4ac
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