The histogram represents the distributions of boiling temperatures, in degrees Celsius, of tap water and a

mixture of salt water.

Boiling Temperatures

10

9

8

7

6

Number

of

Trials

5

-Tap Water

Salt Water

4 3

N

1

0

98°C

99 C 100C 101 102 103 104°C

Temperature (°C)

The mean boiling temperature of the tap water is 2°C less than hat of the mixture of salt water.

Step-by-step explanation:

The complete question is attached below.

From the provided data it can be seen that the distributions of boiling  temperatures, in degrees Celsius, of both tap water and a  mixture of salt water are approximately symmetric.

It is known that, for a symmetric distribution,

Mean = Median = Mode

The median for the two distributions are:

Median (Tap water) = 100°C

Median (Mixture of salt water) = 102°C

Then the mean for the two distributions would be:

Mean (Tap water) = 100°C

Mean (Mixture of salt water) = 102°C

So, the mean boiling temperature of the tap water is 2°C less than hat of the mixture of salt water.

if you mean

then it's c. 8, -7/3

but if you mean

then it is

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.