Jenna drives on average 46 miles per day with a standard deviation of 5.3 miles per day. Suppose Jenna's miles driven per day are normally distributed. Let X = the number of miles driven in a given day. Then X - N(46, 5.3). If necessary, round to three decimal places. Provide your answer below:
Suppose Jenna drives 41 miles on Monday. The Z-score when x - 41 is . The mean is This z-score tells you that x = 41 is standard deviations to the left of the mean.

Suppose Jenna drives 41 miles on Monday. The Z-score when x - 41 is    .   The mean is    This z-score tells you that x = 41 is    standard deviations to the left of the mean.

Step-by-step explanation:

From the question we are told that

  The  mean is  

  The standard deviation is  

   The  value of =  41

Generally the z-score is mathematically represented as

substituting values  

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)