(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Step-by-step explanation:

First,  lets remove the brackets.  There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a)  ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³    (1)  and

-5b³ +...b³=b³    (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³  So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly   lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)