The weights of certain machine components are normally distributed with a mean of 8.61 g and a standard deviation of 0.07 g. Find the two weights that separate the top 3% and the bottom 3%. Theses weights could serve as limits used to identify which components should be rejected

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96