I’ll give brainliest! Using CPCTC
Anglese
Given: AD BC and BCD -
ZADC
Prove: DE - CE

1. AD ≅ BC    [Given]

2. ∠ADC ≅ ∠BCD    [Given]

3. DC ≅ DC    [reflexive property]

4. ΔADC ≅ ΔBCD    [SAS]

5. ∠DAE ≅ ∠CBE    [CPCTC]

6. ∠DEA ≅ ∠CEB    [def. of vertical angles]  

7. ∠DEA ≅ ∠CEB    [vertical angles theorem]

8. ΔAED ≅ ΔBEC    [AAS]

9. DE ≅ CE    [CPCTC]

Step-by-step explanation:

Just finished mine :D

452,489 to the nearest thousand is 452,000

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: