(1 point) A random sample of 1600 home owners in a particular city found 736 home owners who had a swimming pool in their backyard. Find a 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard. Express your results to the nearest hundredth of a percent.

(0.4356,0.4844)

Step-by-step explanation:

Use Ti 84

use function "1-PropZInt".

Enter x = 736

         n = 1600

         c= 0.95

(0.4356,0.4844)

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

7

step-by-step explanation:

i'm assuming you need to figure out how many campers go into each tent.

i got the answer by:

24+4=28

28/4=7