Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin of paint in his store and decides to paint the tank (not the base). If he uses 250 ml to cover 1 m2, will he have enough paint to cover the tank with one layer of paint? [take π=3.142] Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin of paint in his store and decides to paint the tank (not the base). If he uses 250 ml to cover 1 m2, will he have enough paint to cover the tank with one layer of paint? [take π=3.142]

Step-by-step explanation:

Height of the cylinder = 1.4 m

diameter of the cylinder = 1.1 m

Tublu has a full 2 litre tin of paint  

Assume that the tank has an open top to allow the capturing of rainwater.

Also, Tublu does not need to paint the base of the tanks.

Tublu needs 250 ml to cover 1 m^2 of the tank body

Only the body of the tank is to be painted, so we find the perimeter of the tank body.

from basic circle mensuration, perimeter of the tank body =  

where d is the diameter of the tank

==> 3.142 x 1.1 = 3.456 m

If we imagine that this perimeter of the tank body is spread out, it will form a rectangle with a height of 1.4 m from the base.

The area of this rectangle that will be formed =  (perimeter of the cylinder body) x ( height of the cylinder)

==> 3.456 x 1.4 = 4.838 m^2

this area is the area of the tank that needs to be painted.

Now we convert the 250 ml to litre,  we'll have

250 ml = 250 x 10^-3 litres = 0.25 litres

Since 250 ml or rather 0.25 litres of paint is needed to cover 1 m^2 area of the tank's body, then, we will need

==> 4.838 x 0.25 = 1.21 litres of paint

Since Tublu has a full 2 litres tin of paint, and he needs 1.21 litres  to cover the body of the tank, then we can say that Tublu has more than enough paint to cover the tank surface in one layer coating.

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation: