Mrs. Carlyle bought a bag of peanuts for her children. when Philip Joy Brent and Preston came home from school and they each took some peanuts from the bag. Phillip took 1/3 of peanuts from the bag Joy took 1/4 of the remaining peanuts. Brent 1/2 of the remaining peanuts. Preston took 10 peanuts there 71 peanuts remaining in the bag. how many peanuts were originally in the bag? how many peanuts in each child take?

Total peanut=324

Step-by-step explanation:

Let the peanut=x

Philip took 1/3 of x

Remaining peanut=x-1/3x

=3x-x/3

=2/3x

Joy took 1/4 of the remaining leaving 3/4

Remaining=(3/4)(2x/3)

=6x/12

=1/2x

Brent took 1/2 of those, leaving 1/2

=(1/2)*(1/2x)

=1/4x

Preston took 10

Remaining

1/4x - 10 = 71

1/4x = 81

x=81÷1/4

=81*4/1

x = 324

Total peanut =324

Philip=1/3x

=1/3*324

=108

Remaining 324-108

=216

Joy=1/4 of 216

=54

Remaining

324-108-54=162

Brent=1/2 of 162

=81

Preston=10

Total taken=Philip+joy+Brent+Preston

=108+54+81+10

=253

Total remaining=Total peanut - total taken

=324-253

=71

49%

step-by-step explanation:

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