Given: ∆KLM, KL ≅ LM A∈ KM , B ∈ KM AK ≅ BM Prove:△AKL ≅ △BML ΔALB is isosceles

ΔAKL is congruent to ΔBML by the Side Angle Side rule of congruency and ΔALB is isosceles as two of its sides and are congruent

Step-by-step explanation:

The given parameters are;

The given triangle ΔKLM has sides ≅ ,   Given

ΔKLM is isosceles Δ (two equal segments),         Definition of isosceles Δ

∠LKM ≅ ∠LMK,                                                       Base ∠s of isosceles Δ are ≅

Point A is on segment ,                                  Given    

Point B is also on segment ,                          Given

Segment ≅ segment ,                              Given

ΔAKL ≅ ΔBML,                                                       SAS rule of congruency

Segment ≅ segment ,                                CPCTC

ΔALB is isosceles (two equal segments),            Definition of isosceles Δ

Where:

SAS = Side Angle Side

CPCTC = Congruent parts of congruent triangles are congruent.

step-by-step explanation:

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