The test statistic of z equals = 2.94 2.94 is obtained when testing the claim that p not equals ≠ 0.877 0.877. A. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. B. Find the P-value. C. Using a significance level of alpha α equals = 0.01 0.01, should we reject Upper H 0 H0 or should we fail to reject Upper H 0 H0?

Step-by-step explanation:

The claim being tested is that p not equals ≠ 0.877

A) This is the alternative hypothesis and it is a two tailed test. It means that it can be in either direction.

B)Given that z = 2.94, the p value would be determined from the normal distribution table. Since the curve is symmetrical and it is a two tailed test, the p for the left tail and the right tail would be considered. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area above the test z score in the right tail is 1 - 0.998 = 0.002

We would double this area to include the area in the left tail of z = - 2.94 Thus

p = 0.002 × 2 = 0.004

C) Since alpha, 0.01 > than the p value, 0.004, then we would reject the null hypothesis, H0

i really dont know

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)