he graphed line shown below is y = 3 x minus 1. On a coordinate plane, a line goes through (0, negative 1) and (1, 2). Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions? y + 1 = 3 x y = negative 3 x + 1 y = 3 x + 1 y minus 3 x = negative 3

y + 1 = 3x

Step-by-step explanation:

The graphed line is y = 3x - 1

The options given to us are

y + 1 = 3x

y = -3x + 1

y = 3x + 1

y - 3x = -3

Consider the first equation:

y + 1 = 3x

Substitute (0,-1) into the equation:

-1 + 1 = 3(0)

0=0

Substitute (1,2) into the equation:

2+1 = 3(1)

3 = 3

Thus the equation holds true for the given points.

Rearrange the equation

y + 1 = 3x

y = 3x - 1

As it is the same equation which was initially graphed, both of these lines will be same and overlap each other, resulting in infinite number of solution

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

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