A vertical radio tower is 645 feet high above level ground. How far would you need to be from the base of the tower so that the angle of elevation to the top of the tower would be 35.0°? (The “angle of elevation” is the angle measured from level ground up to the top of the tower.)

921.165 feet

Step-by-step explanation:

Ok we are looking for the length of the base.

Now let's take the question and picture it as a triangle, we will find out that it looks like a right angle triangle.

The height= 645 feet

Angle of elevation= 35°

Base is unknown

To find the base

We recall that tan of angle

= opposite/adjacent

In this case

Angle= 35°

Opposite= height= 645

Adjacent= base

Tan 35 = 645/adj

Adj =645/tan 35

Adj =645/0.7002

Adj = 921.165

The base is 921.165 feet

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

77

step-by-step explanation: