A sample of a radioactive substance has an initial mass of 58.7 . This substance follows a continuous exponential decay model and has a half-life of 5 hours. (a)Let t be the time (in hours) since the start of the experiment, and let y be the amount of the substance at time t . Write a formula relating y to t. y=__ e^__(t) . Use exact expressions to fill in the missing parts of the formula. Do not use approximations. b)How much will be present in 8 hours? Do not round any intermediate computations, and round your answer to the nearest tenth.

a). Y = y0e^-k(t)

b) Y = 19.4 Unit mass

Step-by-step explanation:

Y = y0e^-k(t)

Where y is amount present at the time

Y0 is initial amount present at t = 0

Y0 = 58.7

Half life = 5 hours

At half life , y = 58.7/2

At half life , y = 29.35

K = decaying constant.

Let's look fithe value of k

Y = y0e^-k(t)

29.35 = 58.7e^-k(5)

29.35/58.7 = e^-k(5)

0.5 = e^-k(5)

In 0.5 = -k(5)

-0.69314718 = -k(5)

0.138629436 = k

The value present in 8 hours will be

Y = y0e^-k(t)

Y = 58.7e-0.138629436(8)

Y = 58.7e-1.109035488

Y = 58.7(0.329876978)

Y= 19.36377861

To the nearest tenth

Y = 19.4 unit of mass

i can answer this question sweetie!

step-by-step explanation:

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.