There are 3 times as many fiction books as non fiction in a library 120 books are loaned out and 24 non fiction books there are now twice as many fiction books as non fiction how many books are in the library

N = 43.2

F = 129.6

Total books = F + N = 129.6 + 43.2 = 172.8

Please note that number of books cannot be in fraction, there is some mistake in formulating the question!

But nevertheless, the key concept here is to learn how to set up such algebraic equations.

Step-by-step explanation:

Let F denotes fiction book

Let N denotes non-fiction book

There are 3 times as many fiction books as non-fiction in a library.

Mathematically,

F = 3N          eq. 1

120 fiction books are loaned out and 24 non-fiction books

Mathematically,

F - 120 = remaining fiction books  

N - 24 =  remaining non-fiction books  

There are now twice as many fiction books as non-fiction.

Mathematically,

2(remaining fiction books) = (remaining non-fiction books)

2(F - 120) = (N - 24)         eq. 2

Substitute eq. 1 into eq. 2

2(3N - 120) = (N - 24)

Simplify the equation,

6N - 240 = N - 24

6N - N = 240 - 24

5N = 216

N = 216/5

N = 43.2

Please note that number of books cannot be in fraction, there is some mistake in formulating the question!

But nevertheless, the key concept here is to learn how to set up such algebraic equations.

So back to the problem.

F = 3N

F = 3(43.2)

F = 129.6

So the total books in the library are

Total books = fiction + non-fiction

Total books = F + N = 129.6 + 43.2 = 172.8

F=3N

F-120 = Remaining fiction

N-24 = remaining Non fiction

F=2N

2(F-120)=N-24

2(2N-120)=N-24

4N-240 = N-24

3N=216

N=72

from Eq 1

F=3N

F=3(72)

F=216

total = F+N

total = 216 + 72

total = 288

Step-by-step explanation:

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