Find the solution of the differential equation that satisfies the given initial condition.

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the solution of the differential equation that satisfies the given initial condition. dy/dx = x/y, y(0) = -2

Using the variable separable method.

Step 1: Separate the variables

dy/dx = x/y

x dx = y dy

Step 2: Integrate both sides of the resulting equation

Note that the constant of integration added to the side containing x

Step 3: Apply the initial condition y(0) = -2

This means when x = 0, y = -2. From step 2:

Step 4: Substitute K = 4 into the resulting differential equation above

This gives the solution to the differential equation.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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