Line A B has a negative slope and goes through points (negative m, p) and (w, z). Line A prime B prime has a positive slope and intersects with line A B. Which coordinate for points A' and B' would help prove that lines AB and A'B' are perpendicular? A': (p, m) and B': (z, w) A': (p, m) and B': (z, −w) A': (p, −m) and B': (z, w) A': (p, −m) and B': (z, −w)

(B)A': (p, m) and B': (z, −w)

Step-by-step explanation:

Line AB has a negative slope and goes through points (-m, p) and (w, z).

Line A'B' has a positive slope and intersects with line AB.

Definition: Two lines are perpendicular if the product of their slopes is -1.

Slope of AB

From the options, we consider the coordinates whole slope multiplied by the slope of AB gives a result of -1.

In Option B: A': (p, m) and B': (z, −w)

Slope of A'B'

The product of the slopes

Therefore, the coordinate for points A' and B' which would help prove that lines AB and A'B' are perpendicular is A': (p, m) and B': (z, −w).

You can try to calculate the slope of the others. They would not satisfy this condition.

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)