PLEASE HELP!! AOC and BOD are diameters of a circle, centre O. Prove that triangle ABD and triangle DCA are congruent by RHS.

Answer

3.7/5

6

Siddharta7

Genius

2.1K answers

230.1K people helped

Step-by-step explanation:

Given,

BAD and ADC are right angles[angles in semicircle is 90]

AD is common to both triangles.

=> ∠BAD = ∠CDA[angles in semicircle is 90°]

=> ∠ABO = ∠DCA[angles in same segment are equal]

∴ ΔABD and ΔDCA are congruent. ASA

(or)

BD = CA[diameters of the circle]

=> ∠BAD = ∠CDA[angles in semicircle is 90°]

AD is common to both triangles.

ΔABD and ΔDCA are congruent triangles. RHS

(or)

BD = CA[diameter of circle]

AD is common.

=> ∠ADB = ∠CAD[base angles of an isosceles triangle are equal]

∴ ΔABD and ΔDCA are congruent triangles. SAS

Hope it helps!

what are you trying to solve here

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a