To create an open-top box out of a sheet of cardboard that is 25 inches long and 13 inches wide, you make a square flap of side length x inches in each corner by
13 in.
cutting along one of the flap's sides and folding along the other. (In the diagram,
a solid line segment in the interior of the rectangle indicates a cut, while a
dashed line segment indicates a fold.) Once you fold up the four sides of the
box, you glue each flap to the side it overlaps. To the nearest tenth, find the value of x that maximizes the
volume of the box.

Step-by-step explanation:

length of the box is a = 25 -2x

width of the box is b =13 -2x

height of the box is x

and x < 6,5

so the volume of the box V=f(x) = x.(25-2x)(13-2x)= 4x^3 -76x^2 +325x

f'(x) = 12x^2 - 152x + 325

to maximize the volume of the box ( f(x) max ) then f'(x) = 0 --> x ≈ 2,72 and x ≈ 9,94

so x = 2,72 inches

length of the box is a = 25 -2x

width of the box is b =13 -2x

height of the box is x

and x < 6,5

so the volume of the box V=f(x) = x.(25-2x)(13-2x)= 4x^3 -76x^2 +325x

f'(x) = 12x^2 - 152x + 325

to maximize the volume of the box ( f(x) max ) then f'(x) = 0 --> x ≈ 2,72 and x ≈ 9,94

so x = 2,72 inches

Step-by-step explanation:

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

answer: on kudzu, being female and being green are independent events.

step-by-step explanation: