Question 5 Multiple Choice Worth 1 points) (04.02 MC)
The equation of fine WX is 2x + y = -5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (-1,-2)?
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7:36 PM
7/14/2020
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The equation is 2y = x-3

Step-by-step explanation:

Equation of WX is;

2x + y = -5

Can be written as;

y = -5 -2x

compare it with standard form

y = mx + c

where m is slope and c is intercept.

Slope of the line is thus -2

The second line is perpendicular to WX

this means that the product of their slopes is -1

Mathematically;

-2 * slope of second line = -1

Slope of second line is -1/-2 = 1/2

Now we use the point slope form to get the equation of that second line

Mathematically;

y-y1 = m(x-x1)

y-(-2) = 1/2(x-(-1))

y + 2 = 1/2(x + 1)

2(y + 2) = x + 1

2y + 4 = x + 1

2y = x + 1-4

2y = x-3

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option