Mathematics, 16.07.2020 05:01 joseaguilaroux4zh

An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of moving violations for which the individual was cited during the last 3 years. The pmf of Y is: Compute E(Y) Suppose an individual with Y violations incurs a surcharge of $100Y2. Calculate the expected amount of the surcharge.

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Answer from: nguyenhoangthienkim0

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of moving violations for which the individual was cited during the last 3 years. The pmf of Y is:

y | P(Y)

0 | 0.50

1 | 0.20

2 | 0.25

3 | 0.05

Compute E(Y)

Suppose an individual with Y violations incurs a surcharge of $100Y2. Calculate the expected amount of the surcharge.

The expected value E(Y) is

E(Y) = 0.85

The expected amount of the surcharge is

E(100Y^2) = 165

Step-by-step explanation:

Let Y be the number of moving violations for which the individual was cited during the last 3 years.

The given probability mass function (pmf) of Y is

y | P(Y)

0 | 0.50

1 | 0.20

2 | 0.25

3 | 0.05

Compute E(Y)

The expected value E(Y) is given by

$E(Y) = \sum Y \cdot P(Y) \\\\E(Y) = 0 \cdot 0.50 + 1 \cdot 0.20 + 2 \cdot 0.25 + 3 \cdot 0.05 \\\\E(Y) = 0.85$

Suppose an individual with Y violations incurs a surcharge of $100Y2. Calculate the expected amount of the surcharge.

The expected amount of the surcharge is given by

E(100Y^2) = 100E(Y^2)

Where

$E(Y^2) = \sum Y^2 \cdot P(Y) \\\\E(Y^2) = 0^2 \cdot 0.50 + 1^2 \cdot 0.20 + 2^2 \cdot 0.25 + 3^2 \cdot 0.05\\\\E(Y^2) = 1.65$

So, the expected amount of the surcharge is

$E(100Y^2) = 100E(Y^2) \\\\E(100Y^2) = 100 \cdot 1.65 \\\\E(100Y^2) = 165$

Answer from: Quest

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step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

Answer from: Quest

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