AABC has vertices at A(12, 8), B(4,8), and C(4, 14). AXYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14).

AMNO has vertices at M(4. 16), N(4.8), and O(-2.8).

AJKL has vertices at J(14, -2), K(12, 2), and L(20, 4).

are congruent. A

is a single rigid transformation that maps the two congruent triangles.

Triangle ABC and triangle XYZ

Triangle ABC and triangle MNO

Triangle JKL and triangle ABC

Triangle MNO and triangle XYZ

Triangle ABC and triangle MNO are congruent. A Rotation is a single rigid transformation that maps the two congruent triangles.

Step-by-step explanation:

ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).

ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).

Therefore:

and ΔABC ≅ ΔMNO by SSS postulate.

In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.

i dont know

step-by-step explanation:

why didnt you study

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.