Simplify: (2 cot(−240°)cos(-1050°)− cot^2(50°)) / (sec^2(40°))

Thanks! (:

\frac{2\cot \left(-240^{\circ \:}\right)\cos \left(-1050^{\circ \:}\right)-\cot ^2\left(50^{\circ \:}\right)}{\sec ^2\left(40^{\circ \:}\right)}

Step-by-step explanation:

ok

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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