If f(x) = 1 – x, which value is equivalent to |f(i)|?l

Square root ( 2 )

Step-by-step explanation:

We have to determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ).  

the solution is h=10 because you add 9 to each side of the equation.