Aram's four children are now 1, 5, 7, and 9 years old. In how many years will the sum of the ages of two of his children be twice the sum of the ages of the other two children?

In 2 years

Step-by-step explanation:

age right now 1,5,7,9

Let the number of years in which the sum of the ages of two of his children be twice the sum of the ages of the other two children=x

Therefore Age of the children after x years will be 1+x,5+x,7+x and 9+x

2[1+x + 5+x] = (7+x)+(9+x)

2[6+2x]= 7+9+x+x

12+4x=16+2x

4x-2x=16-12

2x=4

x=4/2=2

Let's verify if the answer is correct

-- Verify by substituting the value of x in this 2[1+x + 5+x] = (7+x)+(9+x)

2[1+2 + 5+2] = (7+2)+(9+2)

2[10]=9+11

20=20

Therefore 2 years is the answer

step-by-step explanation:

se a cavasery6

slope =   (y2 -y1) ÷ (x2 -x1)

slope = (0 -0) / (-5, -7)

slope = 0 / -12 = 0

the slope of the line is zero.   it is perfectly horizontal.

step-by-step explanation: