5. Car rental company A charges $30 a days and $0.15 per mile driven. Company B charges $20 a day
and $0.20 per mile driven. How many miles the
renter has to drive before the cost of the car rental
the same? What is the total cost of rental to drive
that many miles?

Step-by-step explanation:

Let the renter drives 'x' miles

Company A:

Rental cost = 30 + 0.15x

Company B:

Rental cost = 20 + 0.20x

Given rental cost are same

20  + 0.20x = 30 + 0.15x

Subtract 20 from both sides

20 + 0.20x - 20 = 30 + 0.15x - 20

    0.20x = 10 + 0.15x

Subtract 0.15x from both sides

0.20x - 0.15x = 10 + 0.15x - 0.15x

  0.05x = 10

Divide both sides by 0.05

0.05x/0.05=10/0.05

x = 1000/5

x = 200

a) The renter has to drive 200 miles

b) Rental cost charged by company A = 30 +0.15*200

                                                                = 30 + 30

                                                               = $ 60

Rental cost charged by company B = 20 + 0.20**200

                                                          = 20 + 40

                                                          = $ 60

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.