X^2 - 12x + 19 in the form of (x + a)^2 + b ???

( x-6)^2 -17

Step-by-step explanation:

X^2 - 12x + 19

we need it in given below form

(x + a)^2 + b

we know that

lets convert that in same form

X^2 - 12x + 19 = x^2 + 2(-6)x + 19

comparing x^2 + 2(-6)x to x^2 + 2ax

we have a -6

now

(x-6)^2 = x^2 + 2(-6)x + 36

36 is missing in the x^2 + 2(-6)x + 19 hence to get that

we add and subtract 36 in the above equation

so we have

x^2 + 2(-6)x + 19 + 36 -36

rearranging  it \

(x^2 + 2(-6)x  + 36) -36 + 19    (x^2 + 2(-6)x  + 36 =( x-6)^2)

=>( x-6)^2 -17

comparing the above equation to

(x + a)^2 + b

we have a = -6

b = -17

( x-6)^2 -17

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

75%

step-by-step explanation: