What is the distance from the origin to point P graphed on the complex plane below? On a coordinate plane, point P is at (2, negative 5). StartRoot 7 EndRoot StartRoot 29 EndRoot 7 29

√29

Step-by-step explanation:

Use the distance formula √((x2-x1)^2+(y2-y1)^2)

Since the first point is on the origin, (x1, y1) is (0, 0)

The second point is (2, -5)

Plug both points into the distance formula to get √29

the answer is B

Step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3