∗+√(+"12 " )= 22 A)32 B)22 C)40 D) 20 + √(&+)= 15 A)15 B)7 C)21 D) 20 5+ √(&(∗(−)^)) = 21 A)32 B)22 C)40 D) 21 [{8 - 3 * 4 + (1 + 1)2}+{ √(&[{(+)}/]∗)}= 60 A)44 B)24 C)60 D) 20 [{20 + 3 * 5 }+{2 √(&[{(+)}/]∗)} = 55 A)135 B)55 C)115 D) 235

6 and 24

step-by-step explanation:

6 x 4 = 24

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: