Which is the graph of the linear inequality 2x – 3y < 12?
B

C.

Step-by-step explanation:

Given

2x - 3y < 12

Required

Find the graph it represents

we start by solving for the x and y intercepts;

Let x = 0

2x - 3y < 12 becomes

2(0) - 3y < 12

0 - 3y < 12

-3y < 12

Divide both sides by -3

-3y/3 < 12/-3

y > -4

Let y = 0

2x - 3y < 12 becomes

2x - 3(0) < 12

2x - 0 < 12

2x < 12

Divide both sides by 2

2x/2 < 12/2

x < 6

So, we have

x < 6 and y > -4

This implies that the graph is bound by the region where the values of x is less than 6 and the values of y is greater than -4

From the list of given options,only option C answers this question. The dotted lines actually represent inequalities

i would pic false cause it goes down towards negative

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)