What's the total surface area of a covered box with a length of 4 ft, a width of 3 ft, and a height of 6 ft? Question 17 options: A) 108 sq ft B) 38 sq ft C) 84 sq ft D) 96 sq ft

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A. 108 ft².

Step-by-step explanation:

Find the area of each face using the dimensions 4, 3 and 6. Remember, there are 6 total faces with 3 sets of congruent faces. The faces are rectangular, so the formula A = l × w will be used to solve for the area of each:

2(4 ·3) = 2(12) = 24 ft²

2(4· 6) = 2(24) = 48 ft²

2(3 · 6) = 2(18) = 36ft².

Add up the areas of the faces:

24 + 48 + 36 = 108 ft².

A) 108 sq ft

Step-by-step explanation:

SA = PH + 2LW

P = 2(L + W)

SA = 2(L + W)H + 2LW

SA = 2(4 ft + 3 ft)(6 ft) + 2(4 ft)(3 ft)

SA = 108 sq ft

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0